12x^5-6x^3+4x^2/4x^2

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Solution for 12x^5-6x^3+4x^2/4x^2 equation: 


x in (-oo:+oo)

12*x^5+((4*x^2)/4)*x^2-(6*x^3) = 0

12*x^5+((4*x^2)/4)*x^2-6*x^3 = 0

12*x^5+x^4-6*x^3 = 0

x^3*(12*x^2+x-6) = 0

12*x^2+x-6 = 0

DELTA = 1^2-(-6*4*12)

DELTA = 289

DELTA > 0

x = (289^(1/2)-1)/(2*12) or x = (-289^(1/2)-1)/(2*12)

x = 2/3 or x = -3/4

x^3 = 0

1*x^3 = 0 // : 1

x^3 = 0

x = 0

x in { -3/4, 2/3, 0 }

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